Suppose the line `(x-2)/(alpha) = (y-2)/(-5) = (z+2)/(2)` lies on the plane `x + 3y - 2z + beta = 0`. Then `(alpha + beta)` is equal to ________.

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lies in the plane x+3y-alpha z +beta=0 . Then, (alpha,beta) equals

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lies in the plane x+3y-alphaz+beta=0 . Then, (alpha, beta) equals

Let the line (x-2)/3 = (y-1)/-5 =(z+2)/2 lie in the plane x+3y - alphaz + beta=0 . Then, (alpha,beta) equals

If the line (x-2)/3 =(y-1)/-5 =(z+2)/2 lies in the plane x+3y - alphaz + beta=0 , then: (alpha, beta)-=

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lie in the plane x+3y-alpha z+ beta=0 then the value of alpha+beta=

If the line (x-2)/(3)=(y+1)/(5)=(z-2)/(2) lies in the plane alpha x+2y+z-beta=0 then (alpha, beta) equals

For real numbers alpha and beta ne 0 , if the point of intersection of the straight lines ( x - alpha)/( 1) = ( y - 1)/( 2) = ( z -1)/( 3) and ( x - 4) / ( beta) = ( y - 6)/( 3) = ( z - 7)/(3) , lies on the plane x + 2y - z = 8 then alpha - beta is equal to

Line (x-2)/alpha=(y-2)/(-3)=(z+2)/2 lies in x+3y-2z+beta=0 then alpha+beta= ?