A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant `K_1` and `K_2` of same area `A//2` and thickness `d//2` are inserted in the space between the plates. The capacitance of the capacitor will be given by :

Options

A. `(epsi_0A)/d(1/2+(K_1K_2)/(2(K_1+K_2)))`
B. `(epsi_0A)/d(1/2+(K_1K_2)/(K_1+K_2))`
C. `(epsi_0A)/d(1/2+(K_1+K_2)/(K_1K_2))`
D. `(epsi_0A)/d(1/2+(2(K_1+K_2))/(K_1K_2))`

Answer

B