Home
Class 12
CHEMISTRY
R-overset(O)overset(||)C-NH(2)+xNaOH +Br...

`R-overset(O)overset(||)C-NH_(2)+xNaOH +Br_(2) to R-NH_(2)+2NaBr +Na_(2)CO_(3) +H_(2)O`
Number of moles of NaOH used in above Hoffmann bromamide reaction is :

A

3

B

4

C

5

D

6

Text Solution

Verified by Experts

The correct Answer is:
B
Balanced reaction is `R-overset(O)overset(||)C-NH_(2)+4NaOH +Br_(2) to R-NH_(2)+2NaBr +Na_(2)CO_(3)+H_(2)O`
Promotional Banner

Topper's Solved these Questions

  • CARBENE AND NITRENE

    MS CHOUHAN|Exercise LEVEL-2 (Comprehension) |19 Videos

  • CARBENE AND NITRENE

    MS CHOUHAN|Exercise LEVEL-2 |5 Videos

  • BIOMOLECULES

    MS CHOUHAN|Exercise LEVEL - 2|5 Videos

  • CARBOXYLIC ACID AND THEIR DERIVATIVES

    MS CHOUHAN|Exercise LEVEL-2( SUBJECTIVE PROBLEMS)|1 Videos

Similar Questions

Explore conceptually related problems

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Number of moles of NaOH consumed in above reaction.

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Which of the following will not give Hoffmann bromamide reaction.

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Product (A) :

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Product (A) is :

CH_(3)-overset(O)overset(||)C-O-CH_(2)-CH_(3)+H-O^(-) to (O= O^(18)) One of the product of the reaction is :

R-overset(O)overset(||)(C)-Hoverset(R-NH_(2))toR-CH=N-R . This reaction gives best yield at :

Phenol overset(NaNO_(2)//H_(2)SO_(4))to B overset(H_(2)O)to C overset(NaOH)toD name of the reaction is

When carboxylic acid reacts with organolithium reagents to give ketones, side reaction sometines occur. For example, HOCH_(2)CH_(2)overset(CH_(3))overset(|)(CH)CH_(2)CH_(2)overset(O)overset(||)COH underset("tetrahydro furan")overset((x) CH_(3)Li)rarr underset(H_(2))overset(NH_(4)Cl)rarr underset("Compound A 63%")(HOCH_(2)CH_(2)overset(CH_(3))overset(|)(CH)CH_(2)CH_(2)-overset(O)overset(||)C)-CH_(3)+ underset(37%)("Compound (B)") Value of (x) in above reaction is :

A posible mechanism for the reaction : 2NO + 2H_(2) to N _(2) + 2H_(2) O is : (i) 2NO + overset(k _(1))hArr N _(2) O _(2) (ii) N _(2) O _(2) + H _(2) overset(k _(2))to N _(2) O + H _(2) O (iii) N _(2)O + H _(2) overset(k _(3)) to N _(2) + H _(2)O If the second step is the rate determining step then rate law may be written as : ?

Ph-overset(O)overset(||)(C)-CH_(3)underset(HCl)overset(NaNO_(2))to(A)underset("heat")overset(AC_(2)O)to(B)overset(H_(3)O^(+))to(C) Product ( C) of the above reaction is :