In a children park an inclined plane is constructede with an angle of incline `45^0` in the middle part figure. Find the acceleration of a boy sliding on it if the friction coefficient between the cloth of the boy and the incline is `0.6 and g=10 m/s^2`.

Explanation

Let m= mass of child `R-mg cos 45^0=0`
`R=mg cos 45^0 = mg/sqrt2`………..i
Net force acting on the boy due to whichit slides down `=mg sin 45^0 -mu R`
`=mg sin 45^0-mu mg cos 45^0`

`mxx10xx(1/sqrt2)-0.6xxmxx10xx(1/sqrt2)`
`=m(5sqrt2-3sqrt2)=mxx2xxsqrt2`
Accelertion `=Force /mass`
`=(m(2sqrt(2)/m`
`=2sqrt2m/s^2`