A block of mass m moving at speed `upsilon` collides with another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.

Explanation

Suppose the second block moves ast speed v towards right after the collision. From the principle of conservation of momentum.
`mv=2mv/or v'=v/2`
Hence, the velocity of separation = v/2 and the velocity of approach= v. By definition , `e=(velocity of the separation)/(velocity of approach)=`(v/2)/v=1/2