The structure of a water molecule is shown in figure. Find the distance of the centre of mass of the molecule from the centre of the oxygen atom.

Explanation

`m_1=16kg`
`x_1=y_1=0`
m_2=1kg`
x_2=-0.96xx10^-10sin52^0m`
`y_2=-0.96xx10^-10cos52^0`
`m_2=1kg, x_3`
`=0.96xx10^-10sin52^0m`
y_3=-0.96xx10^-10cos52^0`
`x_(cm)=(m_1x_1+m_2x_2+m_3x_3_/(m_1+m_2+m_3)`
`=16xx0+1xx(-0.96xx10^-10sin52^0)`
`(+1xx0.96xx10^-10cos52^0)/(1+1+16)=0`
`y_(cm)=(m_1y_1+m_2y_2+m_3y_3)/(m_1+m_2+m_3)`
=16xx0+2xx0.96xx10^-10 cos52^0)/(1+1+16)`
`=(2xx0.96xx10^-10cos52^0)/18`
`=6.4xx10^-12m`