A bullet of mass 25 g is fired horizontally into a ballistic pendulum of mas 5.0 kg and gets embedded in it figure. If the centre of the pendulum rises by a distance of 10 cm, find the speed of the bullet.

Explanation

Mass of bullet =25g=0.025kg
Mass of pendulum = 5 kg
The vertical displacement
`h=10xm=0.1m`
Let it strike, the pendulum with a velocilty u. Let the fiN/Al velocity be v.
`rarr mu=(M+m)v`
`rarr v=m/((M+m))u`
`=0.25/5.025xu=u/201`
using conservation of energy
`0-(1/2)(M+m).u^2=(M+m).g.h`
`rarr u^2/((201)^2)=2x10x0.1=2`
`rarr u201x sqrt2`
`=280m/sec`.