Calculate the value of acceleration due to gravity at a point .5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.8`ms^2`

Explanation

a. the value of g at a height h is (for hltltR)
`g=g_0(1-(2h)/R)`
`=(9.80ms^2)(1-(2xx5.0km)/(6400km))`
=9.78ms^2`
b. The value at a depth h is
`g=g_0(1-h/R)`
=(9.8ms^-2)(1(5.0km)/(6400km))`
`=9.79ms^2`