The gravitational field in a region is given by `E=(2veci+vecj)Nkg^-1` show that no work is done by the gravitational field when particle is move on the line `3y+2x=5`.

Answer

A

Explanation

`vecE=2veci+3vecj`
The field is representd as
`tantheta_13/2`

Again the lihne `3y+2x`
`=5` can be represented as
`tantheta_2=-2/3`
`m_1m_2=-1`
Since the direction of field and the displacement are perpendicular is done by the particle on the line.