Home
Class 11
PHYSICS
What is the acceleration due to gravity ...

What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is `9.80 ms^-2`.

Text Solution

Verified by Experts

The correct Answer is:
B
Let g be the acceleration due to gravity on mount everest
`g'=g(1-(2h)/R)`
`=9.8(1-1796/6400000)`
`.9.8(1-0.00276)`
`=9.0(0.99724)`
`=9.773m/s^2`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Identify the valid statement from the following Mount Everest is the highest mountain in the world.

The value of acceleration due to gravity on the surface of the moon is 1.625 ms^(-2) .

Water is drained from a vertical cylindrical tank by opening a valve at the base of the tank. It is known that the rate at which the water level drops is proportional to the square root of water depth y , where the constant of proportionality k >0 depends on the acceleration due to gravity and the geometry of the hole. If t is measured in minutes and k=1/(15), then the time to drain the tank if the water is 4 m deep to start with is (a) 30 min (b) 45 min (c) 60 min (d) 80 min

Water is drained from a vertical cylindrical tank by opening a valve at the base of the tank. It is known that the rate at which the water level drops is proportional to the square root of water depth y , where the constant of proportionality k >0 depends on the acceleration due to gravity and the geometry of the hole. If t is measured in minutes and k=1/(15), then the time to drain the tank if the water is 4 m deep to start with is (a) 30 min (b) 45 min (c) 60 min (d) 80 min

find the acceleration due to gravity in a mine of depth 640 m if the value at the surfaceis 9.800 ms^-2 . The rdius of the earth is 6400 km.

Suppose the acceleration due to gravity at a place is 10 m/s^2 . Find its value in cm//(min)^2

If the acceleration due to gravity on the moon is one-sixth of that on the earth. What will be the change in length of a second pendulum there so that it may beat a second there ? Take acceleration due to gravity on earth surface =9.8 ms^(-2) .

Calculate the value of acceleration due to gravity at a point .5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.8 ms^2

HC VERMA-GRAVITATION-Exercises
  1. The gravitational potential in a region is given by V=20Nkg^-1(x+y). A...

    Text Solution

    |

  2. The gravitational field in a region is given by E=(2veci+vecj)Nkg^-1 s...

    Text Solution

    |

  3. Find the height over the earth's surface at which the weight of a body...

    Text Solution

    |

  4. What is the acceleration due to gravity on the top of Mount Everest? M...

    Text Solution

    |

  5. find the acceleration due to gravity in a mine of depth 640 m if the v...

    Text Solution

    |

  6. A body is weighed by a spring balance to be 1.000 kg at the north pole...

    Text Solution

    |

  7. A body stretches a spring by a particular length at the earth's surfac...

    Text Solution

    |

  8. At what rate should the earth rotate so that the apparent g at the equ...

    Text Solution

    |

  9. A pendulum having a bob of mas m is hanging in a ship sailing along th...

    Text Solution

    |

  10. The time taken by Mars to revolve round the sun is 1.88 years. Find th...

    Text Solution

    |

  11. The moon takes about 27.3 days to revolve around the earth in a nearly...

    Text Solution

    |

  12. A mars satellite moving in an orbit of radius 9.4xx10^3 km take 27540 ...

    Text Solution

    |

  13. A satellite of mass 1000 kg is supposed to orbit the earth at a height...

    Text Solution

    |

  14. Find the radius of the circular orbit of a satellite moving with an an...

    Text Solution

    |

  15. What is the true weight of an object in a geostationary satellite that...

    Text Solution

    |

  16. The radius of a planet is R1 and a satellite revolves round it in a c...

    Text Solution

    |

  17. find the minimum colatitude which can directly receive a signal from a...

    Text Solution

    |

  18. A particle is fired vertically upward fom earth's surface and it goes ...

    Text Solution

    |

  19. A particle is fired vertically upward with a speed of 15 kms^-1. With ...

    Text Solution

    |

  20. A mass of 6xx10^24 kg (equal to the mass of the earth) is to be compre...

    Text Solution

    |