The radius of a planet is `R_1 ` and a satellite revolves round it in a circle of radius `R_2`. The time period of revolution is T. find the acceleration due to the gravitation of the plane at its surface.

Answer

A, B, C, D

Explanation

`T=2pi (sqrt(R_2^2)/(gR_1^2))`
or, ` T^2=4pi^2 R_2^2/(gR_1^2)`
or `g=(4pi^2)/T^2 R_2^2/R_1^2`
`:.` Acceleration due to gravity of the planet is
`=(4pi^2)/T^2=R_2^2/R_1^2`