The atmospheric pressure on the surface of the earth is about

Explanation

Let the uniform density be `rho` and atmospheric height be h. The pressure at the surfce of the earth would be
`p=rhogh`
`or 1.0xx10^5Nm^-2=(1.3kgm^-3)(9.8ms^-2)h`
`or, h=(1.0xx10^5Nm^-2)/((1.3kgm^-3)(9.8ms^-2))=7850m.`
Even Mount Everest (8848m) would have been outside the atmoshere.