Refer to the previous problem. Suppose, the goldsmith argues that he has not mixed copper or any other material with gold, rather some cavities might have been left inside the ornament. Calcuate the weighs given in that problem.

Answer

A, B, C

Explanation

Given `m_(Au)=36gm`
`-Again ((m_(Au))/(rho_(Au))+V_C)rhoPw+g=2xxg`
` [where `V_c=`volume of cavity]`
`rarr (36/19.3+V_c)xx1=2`
`rarr V_c=2-36/19.3`
`=(36-6)/19.3`
=0.112cm^3`