A piece of ice of mass of `100g` and at temperature `0^(@)C` is put in `200g` of water of `25^(@)` How much ice will melt as the temperature of the water reaches `0^(@)C`? The specific heat capacity of water`= 4200 J kg ^(-1)K^(-1)` and the latent heat of ice `= 3.36 xx 10^(5)J kg^(-1)`

Explanation

The head relacsed as the water cools down from `25^(@)C` to `0^(@)C` is
`Q = ms delta theta = (0.2kg) (4200J kg^(-1)K^(-1)) (25 K) = 21000J`
The amount of ice melted by this much head is given by
`m = (Q)/(L) = (21000J)/(3.4 xx 10^(2)J kg) = 62g`