A calorimeter of water equivalent `15g` contains `165g` of water at `25^(@)C`. Steam at `100^(@)C `is passed through the water for some time .The temperature is increased to `30^(@)C` and the mass of the calorimeter and its contents is increased by `1.5g` Calculate the specific latent heat of vaporization of water. Specific head capacity of water is `1(cal)/g^(@)C`.

Explanation

Let L be the specific intent head of vaporization of water The mass of the steam condensed is `1.5g` Head lost in condensation of steam is
`Q = (1.5g)L`
The condensed water cool from `100^(@)C to 30^(@)C `head lose in this process is
m `Q = (1.5g)(1 calg^(-1)^(@)C)= 105 cal`
Head supplies to the calorimater and to the cold water the srise in temperature from `25^(@)Cto
`Q_(s) = (1.5g + 165 g)(1calg^(-1)^(@)C ^(-1))(5^(@)C) = 900 cal`
If no head is lost to the surerounding
`(1.5g)L + 105 cal= 900 cal`
`or L = 530 cal g`