As `C=(1/V)Q`, can you say that the capacitor`C` is proportion to the charge `Q`?

Consider the situation shown in (figure) what are the signs of q_1 and q_2 ? If the lines are drawn in proportion to the charge, what is the ratio q_1/q_2 ?

A capacitor has capacitance C . Is this information sufficient to know what maximum charge the capacitor can contain? If yes, what is this charge? If no, what other information is needed?

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2)QE , where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1/2 .

A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is Q and the magnitude of the induced charge on each surface of the dielectric is Q' .

In an oscillaing L.C circuit.the maximum charge on the capacitors is Q.The charge on capacitor when the energy is stored equally between the lectric and magnetic field is …….

A parallel plate capacitor is charged by a battery after some time, the battery is disconnected and a dielectric slab with its thicnkess equal to the plate so reparation is insected between the plates. How will (i) the capacitance of the capacitor (ii) potential difference between the plates & (iii) the energy sotred in the capacitor the affected ? Q_(0) -charge V_(0) - potential difference, C_(0) - capacitance, E_(0) electric field. U_(0) - energy spred, before the dielectric slab is inserted. Q_(0)=C_(0) V_(0), (V_(0))/(d), U_(0)=(1)/(2)C_(0)V_(0)^(2)?