If the above capacitor is connected across a `6.0V`battery , find (a)the charge supplied by the battery , (b)the induced charge on the dielectric and (c)the net charge appearing on one of the coated surfaces.

Explanation

Dielectric constant ` = 4, C `
` = 1.42 mu F , v = 6V `
Charge supplied ,
` q = Cv = 1.42 xx 10^(-9) xx 6 `
` = 8.52 xx 10^(-9) C`
charge induced ` = `q (1 - 1 /K ) `
` = 8.52 xx 10^(-9) xx (1 - 0.25) `
` = 6.39 xx 10^(-9) = 6.4 nC`
Net charge apperaing on one coated surface = 2.13 nC` .