A pallel- plate capacitor has plate area `100cm^2` and plate separation 1.0cm.A glass plate (dielectric constant 4.0)are inserted one over the other the fill the space between the plate of the capacitor.Find the new capacitance.

Explanation

Let the capacitance be ` C_1 and C_2`
Net capacitance `C = C_1 = C_2`
Now, ` C = 4.425 xx 10^(-11) F `
` = 44.25 pF.