An average induced emf of 0.20 V appears in a coil when the current in it is changed from 5.0 A in one direction to 5.0 A in the opposite direction in 0.20 s. find the self inductance of the coil.

Explanation

Average `(di)/(dt) = (-5
0 A) -(5
0 A)/(0
20 s) =- 50 A/s` using `invarepsilon =-L(di)/(dt) 0
2 V = L(50 A/s) or, L = (0
2 V)/(50 A/s) =4
0 mH `.