Home
Class 12
PHYSICS
A rod of length l rotates with a uniform...

A rod of length l rotates with a uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the rod is

A

zero

B

`(1)/(2)Blomega^2`

C

`Blomega^2`

D

`2Blomega^2`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    HC VERMA|Exercise Objective 2|10 Videos
  • ELECTROMAGNETIC INDUCTION

    HC VERMA|Exercise EXERCISE|98 Videos
  • ELECTROMAGNETIC INDUCTION

    HC VERMA|Exercise Questions for short answer|10 Videos
  • ELECTRIC FIELD AND POTENTIAL

    HC VERMA|Exercise Exercises|75 Videos
  • ELECTROMAGNETIC WAVES

    HC VERMA|Exercise Exercise|9 Videos

Similar Questions

Explore conceptually related problems

A rod of length l rotates with a small but uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the centre of the rod and an end is

A conducting disc of radius r rotaes with a small but constant angular velocity omega about its axis. A uniform magnetic field B exists parallel to the axis of rotation. Find the motional emf between the centre and the periphery of the disc.

A metal rod length l rotates about on end with a uniform angular velocity omega . A uniform magnetic field vecB exists in the direction of the axis of rotation. Calculate the emf induced between the ends of the rod. Neglect the centripetal force acting on the free electrons as they moving in circular paths.

A square loop of edge a having n turns Is rotated with a uniform angular velocity omega about one of its diagonals which is kept fixed in a horizontal position . A uniform magnetic field B exists in the vertical direction. Find the emf induced in the coil.

A rod of length l is translating at a velocity v making an angle theta with its length. A uniform magnetic field B exists in a direction perpendicualr to the plane of motion. Calculate the emf induced In the rod, Draw a figure representig the induced emf by on equivalent battery.

A wire of length 10cm translates in a direction making an angle of 60^@ with its length. The plane of motion is perpendicular ot a uniform magnetic field of 1.0 T that exists in the space. Find the emf induced between the ends of the rod if the speed of translation of 20 cm s^(-1).

A 20 cm long conducting rod is set into pure translation with a uniform velocity of 10cm s ^(-1) perpendicular to its length. A uniform magnetic field of magnitude 0.10 T exists in a direction perpendicular to the plane of motion. Find emf developed in the rod.

A conducting square loop of side l and resistance R moves in its plane with a uniform velocity v perpendicular ot one of its sides. A uniform and constant magnetic field B exists along the perpendicualr ot the plane of the loop as shown in . The current induced in the loop is

A copper wire bent in the shape of a semicircle of radius r translates in its plane with a constant velocity v. A uniform magnetic field B exists in the direction perpendicular to the plane of the wire. Find the emf induced between the ends of the wire if (a) the velocity is perpendicular ot the diameter joining free ends, (b) the velocity is parallel to this diameter.

A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s^(-1) about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.