A conducting square loop having edges of length2.0 cm is rotated through `180^@` about a diagonal in 0.20s. A magnetic field B exists in the region which si perpendicular to the loop in its initial position. If the average induced emf during the rotation is 20 mV, find the magnitude of the magnetic field.

Explanation

Here ` e=20mV=20xx10^(-3)V`
`A=(2xx(10^(-2))^2)=4xx10^(-4)`
`dt=0.2s,`
`phi=180^(@), phi_1=2 BA`
`e=(d phi)/(dt)=(2 BA)/(dt)`
` implies 20xx10^(-3)=(2xxBxx4xx10^(-4))/(2xx10^(-1))`
` implies 20xx10^(-3)=4xxBxx10^(-30)`
` implies B=(20xx10^(-3))/(4xx10^(-3))=5T`