A 20 cm long conducting rod is set into pure translation with a uniform velocity of `10cm s ^(-1) perpendicular to its length. A uniform magnetic field of magnitude 0.10 T exists in a direction perpendicular to the plane of motion. Find emf developed in the rod.

Explanation

Here`l=20cm, =0.2 m, `
`v=10 cm/s=0.1m//s`
`B=0.10T.`
`(a) F=qvB`
`=1.6xx10^(-19)xx1xx10^(-1)1xx10^(-1)`
`=1.6xx10^(-21)N`
`(b)qE=qvB`
` implies E=1xx10^(-1)xx1xx10^(-2)V//m.`
`This is vreated due to the induced emf.`
`(c ) Motional emf=Bvl`
`=0.1xx0.1xx0.2`
`=2xx10^(-3)V`.