A magnetic flux of `8X10^(-4)` weber is linked with each turn of a 200 - turn coil when thereis an electric current of 4 A in it. Calculate the self inductance of the coil.

Explanation

Here `(d phi)/(dt)=8xx10^(-4) weber, n=200,i=4A`
`or L=(n/i)(d phi)/(dt)`
`=200xx8xx10^(-4)`
`=4xx10^(-2)H.`