A constant current exists in an inductor coil connected to a battery. The coil is short circuited and the battery is removed. Show that the charge flown through the coil after the short circuiting is the same as that which flows in one time constant before the short circuiting.

Explanation

In the wire there is no resistor in the circuit
The heat stored due to the inductor before and after removal of the battery be the same,i.e.
`V_(1) V_(2) =(1/2)(H^2)`
So, the current will also remain same, Thus the change flowing through the conduct in the coil must be same.