The peak value of an alternating current is 5A and its frequency is 60Hz. The rms value and the time taken by current take to reach the peak value starting from zero is:

Options

A. `3.5` A, `(1/240)` s
B. `3.5` A, `(1/360)` s
C. `35` A, `(1/240)` s
D. `4.0` A, `(1/240)` s

Answer

A

Explanation

The rms current is
`i_(rms) = i_0/sqrt(2) = 3.5 A`.
The time period is
`T = 1/v = 1/60 s`.
The current takes one fourth of the time period to reach the peak value starting from zero. Thus, the time required is
`t = T/4 = 1/240 s`.