An AC source is connected to a capacitor. Will the rms current increase, decrease or remain constant if a dielectric slab is inserted into the capacitor?

When an AC source is connected to a capacitor there is a steady-state current in the circuit. Does it mean that the charges jump from one plate to the other to complete the circuit?

A variable frequency ac source is connected to capacito. How will the displacement current change with decrease is frequency.

An AC source is connected to a diode and a resistor in series. Is the current through the resistor AC or DC?

A parallel -plate capacitor having plate area 400 cm ^2 and separation between the plate 1.0mm is connected to a power supply of 100V. A dielectric slab of thickness1.0mm and dielectric constant 5.0 is inserted into the gap .(a)Find the increase in electrostatic energy .(b) If the power supply is now disconnected and the dielectric slab is taken out , find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?

A light bulb and an open coil inductor are connected to an ac source through a key as shown in figure. The switch is closed and after sometime, an iron rod is inserted into the interior of the inductor. The glow of the light bulb (a) increases, (b) decreases, (c) is unchanged, as the iron rod is inserted. Give your answer with reasons.

An inductor coil joined to a 6 V battery draws a steady current of 12 A . This coil is connected to a capacitor and an AC source of rms voltage 6 V in series. If the current in the circuit is in phase with the emf, find the rms current.

A parallel plate capacitor of capacitance 100 microfarad is connected a power supply of 200 V. A dielectric slab of dielectric constant 5 is now inserted into the gap between the plates. (a) Find the extra charge flown through the power supply and the work done by the supply. (b) Find the change in the electrostatic energy of the electric field in the capacitor.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

Shown a parallel plate capacitor with plates of width b and length l . The separation between the platesis d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. (a) Calculate the energy of the system when a length x of the slab is introduced into the capacitor. (b) what force should be applied on the slab to ensure that is goes slowly into the capacitor? Neglect any effect of friction or gravity.