Can you have an `AC` series circuit in which there is a phase difference of (a) `180^0` (b) `120^0` between the emf and the current?

In a series RL circuit, the resitance and inductive reactane are the same. Then the phase difference between the voltage and current in the circuit is

In an electrical circuit, R, I, C and AC voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and current in the circuit, is (pi)/(3). Instead, if C is removed from the circuit, the phase difference is again (pi)/(3). The power factor of the circuit is

A lamp consumes only 25% of the peak power in an ac circuit. The phase difference between the applied voltage and the current is

In a LCR circuit, the voltage across an inductor, capacitor and resitance are 10V, 10V and 30V respectively, what is the phase difference between the applied voltage and the current in the circuit?

An inductor coil is connected to a 12 V battery and drawing a current 24 A, This coil is connected to capacitor and an AC source of rms voltage rating 24 V in the series connection. The phase difference between current and emf is zero. Therms current through the circuit would found to be

An ac voltage is applied to a resistance R and inductor L in series If R and the inductive reactance are both equal to 3Omega the phase difference between the applied voltage and the current in the circuit is :

In an LCR circuit , L = 88 mH and C = 1muF and the value of the resistor is unknown . The AC source has a frequency of 1000 Hz and the phase between emf and current is 70^@ . Calculate the value of R of the resistor .