A coil of inductance `5.0 mH` and negligible resistance is connected to the oscillator giving an output voltage 'ε=(10V)sinωt'.Find the peak currents in the circuit for `omega = 100 s^(-1), 500 s^(-1), 1000 s^(-1)`.

Explanation

Given inductance `=5.0 mH = 0.005 H`.
(a) `omega=100s^-1`
`X_L = omega L xx 100 xx 5/1000``
`=0.5 Omega`
`i= (in_0)/(X_L) = 10/0.5`
`=100/5 = 20 A`
(b) `omega = 500 s^-1`
`X_L =500 xx 5/1000`
`=2.5 Omega`
`i=10/2.5 = 4A`
(c) `omega=1000 s^-1`
`X_L = 1000 xx 5/1000 = 5 Omega`
`i=10/5 = 2A`