The plate current in a triode can be written as
`i_p = k (V_g + (V_p)/(mu))^(3/2)`.
Show that the mutual conductance is proportional to the cube root of the plate current.

Explanation

Since , `i_p= K(V_g + (V_p/mu))^3/2………(1)`
Differentiating the equation
` di_p = K 3/2 (V_g + (V_p/mu))^ 1/2 dV_g `
` rArr di_p/dV_g = 3/2 K (V_g + (V_p/mu))^1/2 `
` g_m = 3/2 K (V_g +V_p/mu)^1/2 ` ………..(2) `
Form (1)
`i_p = [ 3/2 K ( V_g+ (V_p/mu)^1/2]^3 xx K' `
` i_p = K' (g_m)^3 `
` rArr g_m alpha (3 sqrt (i_p)).`