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For the cell reaction Zn(s) +Cu^(2+)(0...

For the cell reaction
`Zn(s) +Cu^(2+)(0.1M) rarr zn^(2+)(0.01M) + Cu(s)`,
If `E^(@)` is the strandard e.m.f. of the cell, then

A

`E=E^(@)`

B

`E gt E^(@)`

C

`E lt E^(@)`

D

`E=0`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=E^(@)-(0.059)/(2) log. ([Zn^(2+)])/([Cu^(2+)])`
`=E^(@)-(0.059)/(2) log. (0.01)/(0.1)`
`=E^(@)-(0.059)/(2) log. (1)/(10)`
or `E=E^(@)+0.0295 " " :. E gt E^(@)`
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