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The e.m.f. of the cell at 25^(@)C Cu"|...

The e.m.f. of the cell at `25^(@)C`
`Cu"|"Cu^(2+)(0.01M)"||"Ag^(+)(0.1M)"|"Ag`
is `[E^(@)(Cu^(2+)"|"Cu)=0.34V, E^(@)(Ag^(+)"|"Ag)=0.80V]`

A

0.46 V

B

1.14 V

C

0.43 V

D

1.11 V

Text Solution

Verified by Experts

The correct Answer is:
A
The cell reaction is :
`Cu(s)+2Ag^(2+) rarr Cu^(2+) +2Ag(s)`
`E=E^(@) -(0.059)/(2) log. ([Cu^(2+)])/([Ag^(+)]^(2))`
`E^(@)=E^(@)(Ag^(+)"|"Ag)-E^(@)(Cu^(2+)"|"Cu)`
`=0.80-0.34= 0.46V`.
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