The coulombs of electricity required for reduction of 1 mol of `MnO_(4)^(-)` to `Mn^(2+)` are :

Options

A. 96500 C
B. `1.93xx10^(5)C`
C. `4.83 xx 10^(5)C`
D. `9.65 xx 10^(6)C`

Answer

C

Explanation

Reduction of `MnO_(4)^(-) ` to `Mn^(2+)` is :
`MnO_(4)^(-) +8H^(+)+5e^(-) rarr Mn^(2+) +4H_(2)O`
Reduction of 1 mol of `MnO_(4)^(-)` requires
`= 5 xx 96500 C = 4.825xx10^(5)C`