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The e.m.f. of the following cell contain...

The e.m.f. of the following cell containing two hydrogen electrodes is :
Pt, `1//2H_(2)(g)"|"H^(+)(10^(-8)M)."||"M^(+)(0.001M)"|"1//2H_(2)(g), Pt`

A

0.295 V

B

0.0295 V

C

0.0590 V

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`E=E^(@)-(0.059)/(1) log. (10^(-8))/(10^(-3))`
`E=E^(@)+0.059 log 10^(5)`
`= 0+0.059xx5=0.295 V`
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