Same amount of electric current is passed through solutions of `AgNO_(3)` and HCl. If 1.08g of silver is obtained in the first case, the amount of hydrogen liberated at S.T.P. in the second case is

Options

A. `112 cm^(3)`
B. `22400 cm^(3)`
C. `224 cm^(3)`
D. `1.008 g`

Answer

A

Explanation

`("Eq. wt. of Ag")/("Eq. wt. of " H_(2))=("Mass of Ag")/("Mass of "H_(2))`
`(108)/(1)=(1.08)/("Mass of "H_(2))`
`:.` Mass of `H_(2) = (1.08)/(108)=10^(-2)g`
`2g` of `H_(2)` occupies at STP `=22400 Cm^(3)`
`10^(-2)` g of `H_(2)` occupies at STP `=112cm^(3)`.