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Resistance of 0.2 M solution of an elec...

Resistance of 0.2 M solution of an electrolyte is `50Omega`. The specific conductance of the solution is `1.3 S m^(-1)`. If resistance of the 0.4 M solution of the same electrolyte is `260 Omega`, its molar conductivity is :

A

`6.25xx10^(-4)S m^(2) "mol"^(-1)`

B

`625xx10^(-4) S m^(2) "mol"^(-1)`

C

`62.5 S m^(2) "mol"^(-1)`

D

`6250 S m^(2) "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`k=1.3 S m^(-1)=1.3xx10^(-2)S cm^(-1)`
`k= 1/R xx (l/a)`
`1.3xx10^(-1)= (1)/(50)xx(l/a)`
`(l/a)= 1.3 xx 10^(-2)xx50=65.0 xx 10^(-2) cm^(-1)`
`Lambda_(m)=(k xx 1000)/(M)`
where `k=1/R xx (l/alpha)=(1)/(26) xx 65.0 xx 10^(-2)`
`Lambda_(m) = (1)/(260) xx (65.0xx10^(-2) xx 1000)/(0.4)`
`=6.25 S "mol"^(-1) cm^(-2)`
`=6.25xx10^(-4) "S mol"^(-1) m^(2)`
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