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Resistance of 0.2 M solution of an elec...

Resistance of 0.2 M solution of an electrolyte is `50Omega`. The specific conductance of the solution is `1.4 S m^(-1)`. If resistance of the 0.5 M solution of the same electrolyte is `280 Omega`. The molar conductivity of 0.5 M solution of the electrolyte in `Sm^(2)"mol"^(-1)` is

A

`5xx10^(-4)`

B

`5xx10^(-3)`

C

`5xx10^(3)`

D

`5xx10^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Resistance of 0.2 M solution `=50` ohm
Conductivity, `k=1.4 Sm^(-1)`
`=1.4xx10^(-2)S cm^(-1)`
Conductivity, `k= 1/R xx G^(**)`
or Cell constant
`G^(**)=Rxx k = 50 xx 1.4 xx 10^(-2)` or `=0.70 cm^(-1)`
For 0.5 M solution,
Conductivity , `k=1/R xx G^(**)`
`=(1)/(280)xx0.70=2.5xx10^(-3)S cm^(-1)`
Molar conductivity,
`Lambda_(m)=(k xx 1000)/(M) = (2.5xx10^(-3)xx 1000)/(0.5)`
`=5S cm^(2) "mol"^(-1)`
or `=5xx10^(-4) S m^(2) "mol"^(-1)`
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