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Two Faraday of electricity is passed thr...

Two Faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cathode is : (at. mass of Cu `=63.5` amu)

A

0 g

B

63.5 g

C

2 g

D

127 g

Text Solution

Verified by Experts

The correct Answer is:
B
`Cu^(2+)+2e^(-) rarr Cu`
2F of electricity deposit 1 mol of copper.
`:.` Mass of copper deposited `=63.5g`
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