A stone is rotated steadily in a horizontal circle with a period T by a string of length 2 If the tension in the string is kept constant and is increased by 1%, what is the percentage change in the time period ?

Options

A. 0.01
B. 0.005
C. 0.02
D. 0.0025

Answer

B

Explanation

here, `mlomega^(2)=F`=force of tension
`mlxx((2pi)/(T))^(2)=F` or `T^(2)propl`
`therefore` `2(DeltaT)/(T)xx100=(1)/(2)(Deltal)/(l)xx100`
% change in `T=(1)/(2)xx% "change "` in l.
=`(1)/(2)xx1=0.5%`