A particle is moving along a circular path with angular speed co about the axis passing through its centre. What will be its angular speed about a point on the other end of the diameter through the instantaneous position of the particle?

Options

A. `2omega`
B. `omega`
C. `(omega)/(2)`
D. `(omega)/(4)`

Answer

C

Explanation

Here, `v=romega_(1)`
Also `v=2romega_(2)`
`therefore` `romega_(1)=2romega_(2)`
`omega_(2)=(omega_(1))/(2)=(omega)/(2)`.