A particle is moving eastwards with a ve...

A particle is moving eastwards with a velocity of 5 `ms^(-1)` In 10 seconds the velocity changes to 5 `ms^(-1)` northwards. The average acceleration in this time is :

`(1)/(sqrt2)ms^(-2)` towards north-east

`(1)/(sqrt2)ms^(-2)` towards north

zero

`(1)/(sqrt2)ms^(-2)` towards north-west

Text Solution

Verified by Experts

The correct Answer is:

Given `v_(i)=5hati` and `v_(f)=5hatj`
`therefore` `veca_(avg)=(5hatj-5hati)/(10)`
=`(1)/(2)hatj-(1)/(2)hati`
`Iveca_(avg)I=(1)/sqrt(2)ms^(-2)`
towards north-west

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