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Two bodies of equal masses revolve in ci...

 Two bodies of equal masses revolve in circular orbits of radii `R_(1)` and `R_(2)` with the same period. Their centripetal forces are in the ratio :

A

`((R_(2))/(R_(1)))^(2)`

B

`(R_(1))/(R_(2))`

C

`((R_(1))/(R_(2)))^(2)`

D

`sqrt(R_(1)R_(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

Here, centripetal force`F=mromega^(2)`
`F=mr((2pi)/(T))^(2)`
`(F_(1))/(F_(2))=(mR_(1)((2pi)/(T))^(2))/(mR_(2)((2pi)/(T))^(2))=(R_(1))/(R_(2))` Hence (b) is the correct choice.
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