A car is moving in a circular path is radius 500 m with a speed of 30 m/s. If the speed is increased at the rate of 2 m/s, the resultant acceleration will be:

Options

A. `2m//s^(2)`
B. `2.5m//s^(2)`
C. `2.7m//s^(2)`
D. `4m//s^(2)`

Answer

C

Explanation

Here, the resultant acceleration is given by
`|veca|=sqrt(a_(c)^(2)+a_(t)^(2))`
here `a_(c)=(v^(2))/(r)=(30xx30)/(500)=(9)/(5)ms^(2)`
Here  `a_(t)=2ms^(-2)`
`therefore`    `|veca_(c)|=sqrt((9=81)/(25)+4)=2.7ms^(-2)`