A point charge is projected along the axis of circular ring of charge Q and radius `10sqrt(2)` cm.' The distance of the point charge from center of ring, where acceleration of charged particle is maximum, will be :

Options

A. 10 cm
B. 20 cm
C. at infinity
D. none of these

Answer

A

Explanation

Where electric field is max , then eleectric force is also max . Therefore , acc . Of particle depends upon the magnitude of force . Electric field is max . At distance
`x = R/(sqrt(2)) = (10sqrt(2))/(sqrt(2)) = 10 cm `