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A charged particle q is fired towards a...

A charged particle q is fired towards another charged particle Q which is fixed , with a speed v . It approaches Q upto a closet distance r and then returns . If q is given speed 2 v , the closest distance of approach would be :

A

r

B

2r

C

r/2

D

r/4

Text Solution

Verified by Experts

The correct Answer is:
D
We have `1/2 mv^(2) = 1/(4piepsilon_(0)) (Qq)/r rArr r prop 1/(v^(2))` .
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