The electric field at a point due to an electric dipole , on an axis inclined at an angle `theta ( lt 90^(@))` to the dipole axis , is perpendicular to the dipole axis , if the angle `theta ` is :

Options

A. `tan^(-1)(2)`
B. `tan^(-1)(1/2)`
C. `tan^(-1)(sqrt(2))`
D. `tan^(-1)(1/(sqrt(2)))`

Answer

C

Explanation

Here , `alpha + theta = 90^(@)`

`tan alpha = 1/2 tan theta `
or ` tan theta 2 tan alpha `
or ` tan thtea = 2 tan (90^(@) - theta )`
or `tan ^(2) theta = 2 `
or ` tan theta = sqrt(2)`
`theta = tan^(-1) (sqrt(2))`