If a charge on the body is 1 nC , then how many electrons are present on the body ?

Options

A. `1.6 xx10^(19)`
B. `6.25 xx10^(9)`
C. `6.25 xx10^(7)`
D. `6.25 xx10^(28)`

Answer

B

Explanation

Given ,
`q = 1 nC = 1xx 1 xx10^(-9) C " " ( :. 1 nC = 1 xx10^(-9) C)`
` e = 1.6 xx10^(-19) `
From the property of quantization charge
q = ne
` n = q/e = (1xx10^(-9))/(1.6 xx10^(-19))`
` = 0.625 xx10^(-9) xx10^(19)`
` = 0.625 xx10^(10)`
` = 6.25 xx10^(9)`