In the given circuit `V_c=50V and R=50 Omega`. The values of C and `V_R` are:

Options

A. `3.3 mF,60V`
B. `0.104mF`
C. `1.6 mu F,30V`
D. `2 mu F, 60V`

Explanation

`V_C^2+V_R^2=V^2`
`50^2+V_R^2=110^2`
`V_R^2=110^2-50^2`
`V_R=sqrt(110^2-50^2)`
`V_R=sqrt(160 times 60)=98V` `V_R=sqrt(160 times 60)/50 (because R = 50 Omega)`
then, `I_v=110/sqrt(R^2+X_C^2) therefore 98/50=110/sqrt(50^2+X_C^2)`
Find `X_c` and Use `X_C=1/(omega C)`
C=0.104 mF