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In an a.c. circuit the resistance R=0.2 ...

In an a.c. circuit the resistance `R=0.2 Omega` At a certain instant `V_A-V_B=0.5V, I=0.5A , (DeltaI)/(Delta t)=8A//s` The inductance of coil is

A

0.05H

B

0.1H

C

0.2H

D

0.03H

Text Solution

Verified by Experts

`V_A-V_B=V_L+V_R= L (dI)/(dt)+RI`
or `L times 8 +0.5 times 0.2=0.5V`
8L=0.5-0.1=0.4
`therefore L=0.05H`s
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