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If ( a + b) : ( b + c ) : ( c + a) = 5 :...

If `( a + b) : ( b + c ) : ( c + a) = 5 : 12 : 11 and a + b + c =28`, then `(1)/( a) : (1)/( b) : ( 1)/( c )` is equal to:

A

`2: 3: 9`

B

`2 : 9 : 3`

C

`9 : 6 : 2`

D

`6 : 9 : 2`

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The correct Answer is:
To solve the problem, we need to find the values of \( a \), \( b \), and \( c \) based on the given ratios and then calculate the ratio of \( \frac{1}{a} : \frac{1}{b} : \frac{1}{c} \). ### Step 1: Set up the equations based on the given ratios Given the ratios: \[ (a + b) : (b + c) : (c + a) = 5 : 12 : 11 \] We can express this in terms of a variable \( x \): \[ a + b = 5x, \quad b + c = 12x, \quad c + a = 11x \] ### Step 2: Add the equations Adding all three equations: \[ (a + b) + (b + c) + (c + a) = 5x + 12x + 11x \] This simplifies to: \[ 2a + 2b + 2c = 28x \] ### Step 3: Relate to the total sum We know from the problem statement that: \[ a + b + c = 28 \] Thus, we can set: \[ 2(a + b + c) = 28x \implies 2 \cdot 28 = 28x \implies 56 = 28x \] From this, we can solve for \( x \): \[ x = 2 \] ### Step 4: Calculate \( a + b \), \( b + c \), and \( c + a \) Now substituting \( x \) back into the equations: \[ a + b = 5x = 5 \cdot 2 = 10 \] \[ b + c = 12x = 12 \cdot 2 = 24 \] \[ c + a = 11x = 11 \cdot 2 = 22 \] ### Step 5: Solve for \( a \), \( b \), and \( c \) We have the following system of equations: 1. \( a + b = 10 \) 2. \( b + c = 24 \) 3. \( c + a = 22 \) From equation 1, we can express \( b \): \[ b = 10 - a \] Substituting \( b \) into equation 2: \[ (10 - a) + c = 24 \implies c = 24 - 10 + a \implies c = 14 + a \] Now substituting \( c \) into equation 3: \[ (14 + a) + a = 22 \implies 14 + 2a = 22 \implies 2a = 8 \implies a = 4 \] Now substituting \( a \) back to find \( b \) and \( c \): \[ b = 10 - 4 = 6 \] \[ c = 14 + 4 = 18 \] ### Step 6: Find the ratio \( \frac{1}{a} : \frac{1}{b} : \frac{1}{c} \) Now we have \( a = 4 \), \( b = 6 \), and \( c = 18 \). We can find: \[ \frac{1}{a} = \frac{1}{4}, \quad \frac{1}{b} = \frac{1}{6}, \quad \frac{1}{c} = \frac{1}{18} \] ### Step 7: Simplify the ratios To find the ratio \( \frac{1}{4} : \frac{1}{6} : \frac{1}{18} \), we can find a common denominator, which is 36: \[ \frac{1}{4} = \frac{9}{36}, \quad \frac{1}{6} = \frac{6}{36}, \quad \frac{1}{18} = \frac{2}{36} \] Thus, the ratio becomes: \[ 9 : 6 : 2 \] ### Final Answer The final ratio \( \frac{1}{a} : \frac{1}{b} : \frac{1}{c} \) is: \[ \boxed{9 : 6 : 2} \]
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