`H_2` S react with `O_2` to form

Options

A. `H_2 O + S`
B. `H_2 O + SO_2`
C. `H_2 O + SO_3`
D. `H_2 SO_4 + S`

Explanation

To solve the problem of what happens when hydrogen sulfide (H₂S) reacts with oxygen (O₂), we can follow these steps:

### Step 1: Write the Reactants
Identify the reactants in the reaction. Here, we have:
- Hydrogen sulfide (H₂S)
- Oxygen (O₂)

### Step 2: Identify the Products
When H₂S reacts with O₂, it produces sulfur (S) and water (H₂O). Thus, the products of the reaction are:
- Sulfur (S)
- Water (H₂O)

### Step 3: Write the Unbalanced Chemical Equation
The unbalanced chemical equation for the reaction can be written as:
\[ \text{H}_2\text{S} + \text{O}_2 \rightarrow \text{S} + \text{H}_2\text{O} \]

### Step 4: Balance the Chemical Equation
To balance the equation, we need to ensure that the number of atoms for each element is the same on both sides of the equation.

The unbalanced equation is:
\[ \text{H}_2\text{S} + \text{O}_2 \rightarrow \text{S} + \text{H}_2\text{O} \]

Balancing the equation:
- There are 2 hydrogen atoms in H₂S and 2 in H₂O, so we need 1 H₂S and 1 H₂O.
- There is 1 sulfur atom in H₂S and 1 in S.
- For oxygen, we have 2 from O₂ and 1 from H₂O, so we need to adjust the coefficients.

The balanced equation becomes:
\[ 2 \text{H}_2\text{S} + 3 \text{O}_2 \rightarrow 2 \text{S} + 2 \text{H}_2\text{O} \]

### Step 5: Classify the Reaction
This reaction is classified as a redox reaction because:
- Hydrogen sulfide (H₂S) is oxidized to sulfur (S).
- Oxygen (O₂) is reduced to water (H₂O).

### Final Answer
When hydrogen sulfide (H₂S) reacts with oxygen (O₂), it forms sulfur (S) and water (H₂O).

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